LG Vu 3 to launch in October, new QuickView cases teased
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- VuTers
- w0P
- 20 Dec 2013
I got the LG L9 first and then I got the Vu 2 which is a stretched version of L9.
I don't know why but for some Reason, I'm loving the Vu 2 the same with the L9.
When you have the Vu 2 or any Vu phone, you'll know what I'm saying.
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- AnonD-189933
- YT@
- 24 Sep 2013
So LG didn’t cancel its Vu series. Maybe there is still a market after all for phones with screens that has 4:3 aspect ratio. It maybe short & stout but the 4:3 aspect ratio is actually better for reading ebooks and web browsing.
Will definitely consider this as my next phablet.
- j
- jray
- Sbc
- 19 Sep 2013
vu fans and LG should start a vu website once you buy you understand have vu iii global
- j
- jray
- Sbc
- 19 Sep 2013
i love my vu iam waiting for global launch i dont get the haters
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- goron
- y$f
- 18 Sep 2013
best phone for books lover
i love my p895, sharp screen, very easy to read at 4:3 ratio.
i hope vu3 comes with sdcard slot
manga lover and comic lover,this is the best phone for them.
every japanese otaku will go for vu3
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- Anonymous
- F%Q
- 18 Sep 2013
Why 4:3? It's so difficult to grip.
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- Jati Royat
- Kg6
- 18 Sep 2013
So this is the competitor of Note 3 and Z Ultra.. A little too late i think..
- J
- Jati Royat
- Kg6
- 18 Sep 2013
Anonymous, 17 Sep 2013How many people bought Vu 2?I don't know there was vu 2.. All i know is just vu 1.. Hehe
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- AnonD-111968
- Ui%
- 17 Sep 2013
yeip, 17 Sep 2013The long explanation:
Any given rectangle with sides "... morea=45deg:
here's the proof:
from sin(a)*cos(a),
this ia a half-angle formula equal to:
0.5sin(2a)=sin(a)*cos(a), or
sin2a=2sin(a)*cos(a)
d/da[sin(2a)]=2cos(2a)
for maximum area, derivative of the function below must be equal to zero:
A = x*y = (d^2)*sin(a)*cos(a)
A = x*y = (d^2)*0.5sin(2a)
dA/da = (d^2)*0.5cos(2a) =0
cos(2a)=90deg
2a=90
a=45deg
2nd proof:
A=xy
Using Pythagorean Theorem:
d^2=x^2+y^2
y=(d^2-x^2)^0.5
y=x(d^2-x^2)^0.5, then
A=((dx)^2-x^4)^0.5
Amax:
A'=0
0=0.5((dx)^2-x^4)^(-0.5)(2dx-4x^3)
0=d-2x^2
x=d/2^0.5
y=(d^2-x^2)^0.5
=(d^2-(d/2^0.5)^2)^0.5
=(d^2-d^2/2)^).5
=d/2^0.5
therefore:
x=y to obtain maximum area:
Amax=xy=(d/2^0.5)(d/2^0.5)=d^2/2
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- Haissac
- K1B
- 17 Sep 2013
4.3 aspect ratio is marvellous for me! Waiting for this VU3 to replace my P895 that Im currently using now
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- AnonD-2005
- K7e
- 17 Sep 2013
is 4:3 compatible with all the apps? if it is then i'm sold...love the 4:3 aspect ratio...
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- Anonymous
- uSS
- 17 Sep 2013
wardroid, 17 Sep 2013Still working for VU?
Hopeless effort!
lg vu series was already sold over 2 millions in south korea alone.
maybe sounds not good for you , but good for others..
( koreans)
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- AnonD-130464
- pT2
- 17 Sep 2013
come on lg get x-series back on line!
- y
- yeip
- N9x
- 17 Sep 2013
Joven, 17 Sep 2013I don't see your point. Still 5" area, doesn't matter ... moreThe long explanation:
Any given rectangle with sides "x" and "y" and diagonal "d", have an "a" angle (a portion of the full 90° angle next to the diagonal) so that:
sen(a) = x/d => x = d*sin(a) [i]
cos(a) = y/d => y = d*cos(a) [ii]
As the area of that rectangle would be simply x*y, the area becomes
A = x*y = (d^2)*sin(a)*cos(a) (because of i and ii)
To get the maximum area you perform
max [A] = max [(d^2)*sin(a)*cos(a)]
Because (d^2) is always positive and independant from the angle "a" in this model,
max [A] = (d^2)max[sin(a)*cos(a)]
And you can find that the angle "a" that maximizes sin(a)*cos(a) is 45° or (pi/4) rad. I won't proof this but here's a Wolfram Alpha link
http://www.wolframalpha.com/input/?i=max(sin(a)*cos(a))
And the only rectangle sporting a 45° semiangle next to it's diagonal is a square. And this is why the squarish the rectangle, the biggest the area is, given it has the same diagonal length than other rectangle.
- w
- wardroid
- 0IF
- 17 Sep 2013
Still working for VU?
Hopeless effort!
- y
- yeipr
- N9x
- 17 Sep 2013
Joven, 17 Sep 2013I don't see your point. Still 5" area, doesn't matter ... moreNo, he's right. The 5'' are the diagonal (corner to corner) measure of the screen. Given a diagonal, the squarish the shape is, the bigger the area. In faqct, given a fixed diagonal, the largest "rectangle" you can have around it in terms of area is a square. So Squarish is indeed bigger.
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- AnonD-187571
- M$x
- 17 Sep 2013
AnonD-669, 17 Sep 2013Stupid looking phone from LGNo, definitely stylish !
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- AnonD-187571
- M$x
- 17 Sep 2013
Lenny, 17 Sep 2013How many people knew there was a Vu 1? Many of people interested in mobile devices except you...
- J
- Joven
- ncx
- 17 Sep 2013
Iskander, 17 Sep 2013NEED, just NEED! People that whine about the aspect rati... moreI don't see your point. Still 5" area, doesn't matter aspect ratio
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- AnonD-178647
- URH
- 17 Sep 2013
AnonD-669, 17 Sep 2013Stupid looking phone from LGLOL. agree.